The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity

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The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity

The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can be stopped by applying the voltage of 0.35 V when the radiation 256.7 nm is used. Calculate the work function for silver metal.

We know Energy of the incident radiation = Work function + KE of photoelectron

  Work function = Energy of the incident

         radiation - KE of photoelectron     ..(1).Now energy of the incident radiation (E) = hv

                                         

The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity
          ..(2)

The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity

Substituting the values in eq. (2), we have  

The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity
  Energy of incident radiation

   

   

The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity

The potential applied gives the kinetic energy to the electron. Hence, the kinetic energy of the electron = 4.4 eV.Substituting the values in eq. (1), we have           Work function  = 4.83 eV - 0.35 eV                                 = 4.48 eV

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