Calculate the wavelength of radiation emitted when electron in a hydrogen atom jumps from n = `oo` to n = 1. The electron in the hydrogen atom jumps from n2 = `oo`to n1 = 1. Now, we know that `:.1/lambda= R(1/(n_1^2)-1/(n_2^2))` `:.1/lambda=1.097xx10^7(1/1-1/oo)=1.097xx10^7` `:.1/(1.097xx10^7)=9.116xx10^-8" " m= 911.6xx10^(-10)m` ∴ λ = 911.6 Å Concept: Dual Nature of Radiation Is there an error in this question or solution? |