Answer
Hint :In order to solve this question we must know few basic information like what is meant by spectral lines. Spectral series are said to be the set of wavelengths arranged in a sequential fashion which characterizes light or any electromagnetic radiation emitted by the energised atoms.
Complete Step By Step Answer:
Hydrogen atom is said to be the simplest atomic system found in nature, thus it produces the simplest of the spectral series.When electrons de-excite from higher energy level ( $ n_2 $ ) to lower energy level ( $ n_1 $ ) in atomic sample, then number of spectral line observed in the spectrum is given by the formula; $ Total{\text{ }}no{\text{ }}of{\text{ }}the{\text{ }}spectral{\text{ }}lines\; = \dfrac{{\left( {n_2 - n_1} \right)\left( {n_2 - n_1 + 1} \right)}}{2} $ Since it is given in the question that in hydrogen atom electron jumps from $ n_2 = 5\; $ to $ n_1 = 1\; $ Therefore the total no of the spectral line is found to be; $ Total{\text{ }}no{\text{ }}of{\text{ }}the{\text{ }}spectral{\text{ }}lines\; = \dfrac{{\left( {5 - 1} \right)\left( {5 - 1 + 1} \right)}}{2} $ $ Total{\text{ }}no{\text{ }}of{\text{ }}the{\text{ }}spectral{\text{ }}lines\; = 10 $ So, the ten lines are; $ 5 \to 4,5 \to 3,5 \to 2,5 \to 1,4 \to 3,4 \to 2,4 \to 1,3 \to 2,3 \to 1,2 \to 1\; $ are possible in this case.Balmer series is displayed when electron transition takes place from higher energy states ( $ {{\mathbf{n}}_{\mathbf{h}}} = {\mathbf{3}},{\mathbf{4}},{\mathbf{5}},{\mathbf{6}},{\mathbf{7}}, \ldots $ ) to $ {{\mathbf{n}}_{\mathbf{l}}} = {\mathbf{2}} $ energy state. For Balmer series, $ {n_l} = 2 $ and $ {n_h} = 3,4,5 $ Thus, $ 5 \to 2,4 \to 2,3 \to 2\; $ it shows three lines lie in the visible region. Hence the final answer is three spectral lines lie in the visible region for the hydrogen atom when electrons jump from $ n_2 = 5\; $ to $ n_1 = 1\; $ in the visible region.Note :
All the wavelength of the Balmer series falls in the visible part of the electromagnetic spectrum( $ 400nm{\text{ }}to{\text{ }}740nm $ ). Other series are lyman series, paschen series, bracket series, pfund series, Humphreys series. The series is observed at a higher wavelength. The spectral lines are extremely faint and widely spread out. They correspond to highly rare atomic events.Text Solution
Solution : When an electron jumps down from 5th Bohr orbit to 3rd Bohr orbiit in H atom it can jump directly or it can jump to 4th Bohr orbit first and from it, jump to the 3rd Bohr orbit. Thus, we get 3 spectral lines for these 3 transitions. <br> <img src="//d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_CHE_XI_P1_U02_E04_022_S01.png" width="80%">.
How many spectral lines will be observed when an electron jumps from the 5th excited state to the ground state in the visible line spectra of H spectrum?
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