Are uniform acceleration of 4 Metre per second what distance will it cover in 10 seconds after start?

A racing car has a uniform acceleration of 4 m s−2. What distance will it cover in 10 s after start?

Initial velocity of the racing car, u = 0 (since the racing car is initially at rest)

Acceleration, a = 4 m/s2

Time taken, t = 10 s

According to the second equation of motion:

`s=ut+1/2at^2`

Where, s is the distance covered by the racing car

`s=0+1/2xx4xx(10)^2=400/2=200m`

Hence, the distance covered by the racing car after 10 s from start is 200 m.

Concept: Equations of Motion by Graphical Method - Derivation of Velocity - Time Relation by Graphical Method

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Text Solution

Solution : Initial Velocity of the car, u = 0`ms^(-1)` <br> Acceleration, a = 4m `s^(-2)` <br> Time, t = 10 s <br> We know Distance, s = ut + (1/2) `at^(2)` <br> Therefore, Distance covered by car in 10 second = `0xx10+(1//2)xx4xx102` <br> = `0+(1//2)xx4xx10xx10m ` <br> = `(1//2) xx400m ` <br> = 200m

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