What mass of carbon monoxide has the same number of oxygen atoms as are present in 22 grams of CO2?

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Text Solution

Solution : Step I : No. of the oxygen atoms in 22 g of `CO_(2)` <br> Molar mass of `CO_(2)+12 + 2 xx 16 = 44 g` <br> 44g of `CO_(2)` represent = 1 mol <br> 22g of `CO_(2)` represent `= (1mol) xx((22g))/((44g))=0.5 mol` <br> Now, 1 mole of `CO_(2)` contain oxygen atoms `= 2xx 6.022 xx 10^(23)` <br> `0.5` moles of `CO_(2)` contain oxygen atoms `= 2xx 6.022 xx 10^(23) xx 0.5 = 6.022 xx 10^(23)` atoms <br> Step II. Weight of carbon monoxide <br> Molar mass of `CO=12+16 = 28` g By definitioon, `6.022 xx 10^(23)` atoms (or 1 mole oxygen atoms) are present in CO = 28 g.