Answer VerifiedHint: Acceleration of a particle executing simple harmonic motion can be given to be equal to the second-order derivative of the displacement of the particle. We know the displacement of a particle executing SHM is given in terms of its amplitude and sine of its phase. Complete step by step answer: Therefore, the correct option is (C). Note: We must be careful while comparing the equation given in the question to that of the general equation of SHM. Sometimes, instead of the value of angular frequency, the value of time may be provided; in that case, we need to compare the coefficients of the angular frequency and not time. The phase difference between displacement and acceleration of a particle performing S.H.M. is _______. (A) `pi/2rad` (B) π rad (C) 2π rad (D)`(3pi)/2rad` Concept: Some Systems Executing Simple Harmonic Motion Is there an error in this question or solution? |