CBSE 11-science - Physics Please give answer
Asked by ankurgoyal616 | 27 Sep, 2022, 03:07: PM ANSWERED BY EXPERT
CBSE 11-science - Physics please solve it sir
Asked by satishkashyap02022004 | 29 Apr, 2020, 03:07: PM ANSWERED BY EXPERT
Q: Find the percentage decrease in the weight of the body when taken to a depth of 32 Km below the surface of earth. Sol: Weight of the body at depth d is $\large m g’ = m g(1-\frac{d}{R})$ % decrease in weight $\large = \frac{mg-mg’}{mg}\times 100$ $\large = \frac{d}{R}\times 100$ $\large = \frac{32}{6400}\times 100$ = 0.5 % Text Solution 0.6%0.2%0.5%0.7% Answer : C Solution : Here , `d=32 km, R=6400 km` <br> Weight of body at depth `d` is `=mg'=mg(1-d/R)` <br> `%` decrease in weight `=(mg-mg')/(mg)` <br> `=d/Rxx100=32/6400xx100=0.5%` |