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1. Here, t = 6 s u = 0 Distance traversed in 6 s s1 = ut + ½gt2 = ½ × 9.8 × 62 = 176.4 m Let t1 be the time elapsed before last two seconds t1 = 6 – 2 = 4 s Distance traversed in 4 s s2 = ut + ½gt2 = ½ × 9.8 × 42 = 78.4 m Distance covered in last two seconds = s1 – s2 = 176.4 – 78.4 = 98 m 2. Here, u = 20 ms-1 g = 10 ms-2 t = 3 s s = ut + ½ (-g)t2 => s = 20×3 – ½×10×32 => s = 60 – 45 => s = 15 m Distance traversed = 15 m
1. s = 0.5 g t 2 Distance travelled in first 4 seconds = 0.5 * 10 * 42 = 80 m Distance travelled in 6 seconds = 0.5 * 10 * 62 = 180 m Distance travelled in last 2 seconds = 180 - 80 = 100m 2. s = ut - 0.5 g t2 = 20*3 - 0.5*10*32 = 60 - 45 = 15 m |